answer all the Questions please..
if u know, then only answer okay..please..
Answers
Google it , u will find a accurate answer. Why I'm feeling like this is R.S Aggarwal 9th book
Then, in case of supplementary angles:
x+x=180°⇒2x=180°⇒x=90°x+x=180°⇒2x=180°⇒x=90°
Hence, measure of the angle that is equal to its supplement is 90°90°.
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Question 5:
Find the measure of an angle which is 36° more than its complement.
ANSWER:
Let the measure of the required angle be x°x°.
Then, measure of its complement =(90−x)°=90-x°.
Therefore,
x−(90°−x)=36°⇒2x=126°⇒x=63°x-90°-x=36°⇒2x=126°⇒x=63°
Hence, the measure of the required angle is 63°63°.
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Question 6:
Find the measure of an angle which is 30° less than its supplement.
ANSWER:
Let the measure of the angle be x°.
∴ Supplement of x° = 180° − x°
It is given that,
(180° − x°) − x° = 30°
⇒ 180° − 2x°= 30°
⇒ 2x° = 180° − 30° = 150°
⇒ x° = 75°
Thus, the measure of the angle is 75°.
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Question 7:
Find the angle which is four times its complement.
ANSWER:
Let the measure of the required angle be xx.
Then, measure of its complement =(90°−x)=90°-x.
Therefore,
x=(90°−x)4⇒x=360°−4x⇒5x=360°⇒x=72°x=90°-x4⇒x=360°-4x⇒5x=360°⇒x=72°
Hence, the measure of the required angle is 72°72°.
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Question 8:
Find the angle which is five times its supplement.
ANSWER:
Let the measure of the required angle be xx.
Then, measure of its supplement =(180°−x)=180°-x.
Therefore,
x=(180°−x)5⇒x=900°−5x⇒6x=900°⇒x=150°x=180°-x5⇒x=900°-5x⇒6x=900°⇒x=150°
Hence, the measure of the required angle is 150°150°.
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Question 9:
Find the angle whose supplement is four times its complement.
ANSWER:
Let the measure of the required angle be x°x°.
Then, measure of its complement =(90−x)°=90-x°.
And, measure of its supplement