Question

answer and get 50 points

Answer 1

Answer:

(

2

1

)(1+

1+4log

2

x

)

f(x)=2

x(x+1)

, i.e., y=2

x(x+1)

,

⇒log

2

y=x(x−1)=x

2

−x

⇒x

2

−x−log

2

y=0

⇒x=

2

1±

1+4log

2

y

Since x∈[1,∞) ∴ -ve sign is ruled out.

∴⇒x=

2

1

(1+

1+4log

2

y

)

⇒f

−1

(x)=

2

1

(1+

1+4log

2

y

)

⇒f

−1

(x)=

2

1

(1+

1+4log

2

Step-by-step explanation:

Answer 2

Answer:

i dont know but i think it is 2nd

Step-by-step explanation: