Question

answer and solution of 74 question

Answer 1

2x sq. units is the answer

Answer 2

Given:ar(ABCD)=x

ar(ADC)=ar(ABC) [Diagonal divides the

parallelogram in 2 equal

triangles]

ar(ABC)=x/2

In parallelogram ACPQ

ar(ABC)=1/2ar(ACPQ) [area of triangle on

the same base n

b/w same parallels as

that of a parallelogram is

1/2that of the parallelogram]

But ar(ABC)=x/2 [proved]

so,

1/2ar(ABCD)=1/2ar(APQC)

ar(ABCD)=ar(APQC).