Question

answer any one but correctly​

Answer 1

Given :-

It is given that :

• Length of the rectangle = $\tt 3\dfrac{2}{4}m$
• Breadth of the rectangle = $\tt 2\dfrac{1}{4}m$

To find :-

We bave to find the area and perimeter of the rectangle.

Solution :-

• Length = $\tt 3\dfrac{2}{4}m=\dfrac{7}{2}m$
• Breadth = $\tt 2\dfrac{1}{4}m=\dfrac{9}{4}m$

Area of a rectangle = Length × Breadth

$\tt Area = \dfrac{7}{2}\times\dfrac{9}{4}$

$\tt Area=\dfrac{63}{8}m^2$

Perimeter of a rectangle = 2(Length + Breadth)

$\tt Perimeter = 2(\dfrac{7}{2}m+\dfrac{9}{4}m)$

$\tt Perimeter = 2(\dfrac{14+9}{4}m$

$\tt Perimeter = 2(\dfrac{23}{4}m)$

$\tt Perimeter = \dfrac{23}{2}m$