Question

Answer any questions out of these

Answer 1

Answer

Step by step explanation

3) given,

The zeroes are 4,-1,6

We know that

Alpha=4,beta=-1,gama=6

So sum of zeroes=Alpha+beta+gama

=4-1+6

=11

We know

-(coefficient of x^2)/(coefficient of x^3)

=-(-11)/1

=11

Alpha +beta+gama=-b/a

Sum of the product of the zeroes

=Alpha×beta+beta×gama+gama×alpha

=4×(-1)+(-1)×6+6×4

=-4-6+24

=-10+24

=14

We know that

=C/a=14/1=14

Alpha×beta+beta×gama+gama×alpha

=C/a

Product of zeroes=alpha×beta×gama

=4×(-1)×6

=-4×6

=-24

-d/a=-24/1

=-24

So a=1,b=-11,c=14,d=-24

Cubic polynomial is

X^3-11x^2+14x-24