Answer any TWO of the following.
2 x 5 = 10
30. In young's double slit experiment, deduce the conditions for constructive and
destructive interference at a point on the screen.
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Point C is equidistant from both the slits. The intensity of light will be maximum at this point because the path difference of the waves reaching this point will be zero. For constructive interference, the path difference is an integral multiple of wavelengths, that is, path difference is nλ.
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