Question

answer anyone please​

Answer 1

Step-by-step explanation:

...I hope this will help u....

Answer 2

$\frac{sin \theta - 2 {sin}^{3} \theta }{2 {cos}^{3} \theta - cos \theta } \\ \\ = \frac{sin \theta(1 - 2 {sin}^{2} \theta) }{cos \theta(2 {cos}^{2} \theta - 1) } \\ \\ = \frac{sin \theta \times cos2 \theta}{cos \theta \times cos2 \theta} \\ \\ = tan \theta$