Question

answer as fast as you can number 3

Answer 1

That's difficult to answer by writing.

But let me try.

Let AB be the radius of the larger circle.

So, AB = 5cm

Let CD be radius of smaller circle.

So, CD = 3cm.

Let these two circles intersect at two points P, and Q.

Join PQ.

We know what is the length of AC = 5 +3 = 8 cm

If we can tell that Dis midpoint of AC then your question is solved.

You know Any line joined from the centre to the chord bisects it perpendicularly.

So, AD bisects PQ.

Hence, PD = PQ.

Similarly, CD bisects PQ.

Since they bisect the same line

Therefore, AD = CD

or, D is midpoint of AC.

(NOTE : YOU CAN SIMPLY SAY THIS BY TELLING THAT EQUAL CHORDS ARE EQUIDISTANT FROM CENTRE. SINCE PQ IS COMMON, THEREFORE AD = CD..)

Now Join AP.

AP is the radius of the larger circle.

So, AP = 5cm

We now know that AD = 1/2 x AC = 4cm

Use pythagoras theorem.

Hence, you will find that PD = 3cm {(5²) - (4²) = (PD²) So, PD = √9 = 3cm}

∴ PD = DQ = 3cm.

Hence, PQ = PD + DQ = 3 + 3 = 6 cm.

Hope this helps you.

Please mark it as the brainliest answer.

Thank you...