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A circuit diagram with a power source labeled negative positive V and two parallel resistors 15 Ohms and 40 Ohms. There are two vectors in a clockwise direction labeled I.
Round your answers to one decimal place.
This parallel circuit has two resistors at 15 and 40 ohms. What is the total resistance?
____Ω
If there is a 12 V battery in the circuit, what would the approximate current be?
____ A
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We know that,
» The reciprocal of the combined resistance of a number of resistance connected in parallel is equal to the sum of the reciprocal of all the individual resistances. .i.e.,
1/R = 1/R₁ + 1/R₂
By substituting the values in the formula,
➛ 1/R₁₂ = 1/R₁ + 1/R₂
➛ 1/R₁₂ = 1/15 + 1/40
➛ 1/R₁₂ = 8 + 3/120
➛ 1/R₁₂ = 11/120
➛ R₁₂ = 120/11
➛ R₁₂ = 10.9 ohms
Thus, the total resistance of the circuit is 10.9 ohms.
Now, using ohms law that is,
» At constant temperature the current flowing through a conductor is directly proportional to the potential difference across its ends.
Formula : V = RI
where,
- V denotes potential difference
- R denotes resistance
- I denotes current
substituting all the given values in the formula,
➛ V = RI
➛ 12 = (10.9)I
➛ I = 12/10.9
➛ I = 1.1 A
Thus, the current flowing through the circuit is 1.1 ampere.
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