Question

answer asap please find pleaseee​

Answer 1

Answer:

Angle( KOJ ) =  90  ,  Angle( KOL )  =  90

Step-by-step explanation:

angle( KLM = 130 )     angle( KJM = 68 )

in tra KJM

 kj = jm

=  Angle( JKM )  =  Angle( KJM ) = x

by using angle sum property = 180

Angle( JKM ) + Angle( KMJ ) + Angle( KJM ) = 180

 x    +      x    +  68   = 180

2x    =  180 - 68

x = 112 / 2

x  = 56   = Angle( MKJ )  = Angle( OKJ )  

In  Tri KOJ  

let  angle( KOJ  ) = y

angle sum property  =   180

Angle( KOJ )  + Angle( OKJ )  +  Angle( KJM / 2 )  = 180

y   +  56  +  68 /2 = 180

y +  56 + 34 = 180

y + 90 = 180

y = 90 =  Angle( KOJ )  

by linear pair of line LJ = 180

Let Angle( KOL ) be ' z '

 Angle( KOJ  )  +  Angle( KOL )  = 180

  90  +    z  =  180

   z   =  90   =  Angle( KOL )

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