Question

answer both the question ASAP​

Answer 1

Step-by-step explanation:

i explained it step by step hope...it'll help uh..... bbye

Answer 2

Step-by-step explanation:

question 1

given:∆ABC is any triangle

to prove:angleABC+angleACB+angleBAC

draw a line parallel to seg BC, passing through point A.

On the line take pointsP and Q such P-A-Q

Proof:line PQ || BC seg AB is transversal

<ABC=<PAR(alternate angles1)

linePQll line BC and segAC is transversal

<ABC=<QAC(alternate angles2)

angle PAB+BAC+QAC=180

(angles in linear pair3)

as smilar

From 1,2&3

angle ABC + ACB + BAC=

PAB+QAC+BAC=180,From 3 we proved angle A, B&C

are three angle of triangle

there sum=180.