Question

answer both the questions correctly with full procedure and I will mark you as brainliest......​

Answer 1

I hope this helps..
Comment if u find any doubts

Answer 2

Q1)

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(2) ANSWER

THE VERTICAL DISTANCE TRAVELLED BY BALL 1 BY T = 18 s

$= > s1 = u \times t + \frac{1}{2} \times g \times {t}^{2}$

$= > s1 = 0 + \frac{1}{2} \times g \times {18}^{2} \\ \\ = > 162g$

DISTANCE TRAVELLED BY BALL 2 IN 12 s FROM T=6s to 18 s

$= > s2 = v \times 12 + \frac{1}{2} \times g \times {12}^{2} \\ \\ = > s1 = s2 \\ = > 12v = 90g \\ = > v = 7.5g \: or \: 75m {s}^{ - 1}$

Q2)

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(3)

u=3i+4j ; a=0.4i+0.3j

FORMULA

v=u+at

》3i +4j +(0.4i+0.3j)10

》3i +4j+4i +3j

magnitude of velocity =speed

$|v| = speed$

$= > \sqrt{ {7}^{2} + {7}^{2} }$

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