answer both the questions please
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- unique because the 8x-5y=7 and 5y-8x= -7
- Given pair of Linear Equations are:
x +2y = 3
5x + ky +7= 0
The Given equations can be written rewritten as :
x +2y - 3 = 0
5x + ky +7= 0
On Comparing the Given eqs with standard form
a1x + b1y + c1 = 0 & a2x + b2y + c2= 0
Here, a1= 1, b1= 2 , c1= -3 &
a2= 5 , b2= k , c2= 7
A pair of linear equation has unique solution if ,
a1/a2 ≠ b1/b2
⅕ ≠ 2/k
k ≠ 10
So, the lines have unique solution for all real values of k except
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1. here a1/A2 is not equal to b1/B2
unique solution
2. here is no solution
a1/A2=b1/b2not equal to c1/c2
5/1=k/2not equal to 7/3
k=10
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