Answer by physics expert only
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(a) A fuse wire melts at 5 Ampere . If it desired that the fuse wire melt at 10A , then whether the New fuse wire should be of larger or smaller radius than the earlier one ? Give reason for your answer?
(b) If the radius of a current carrying conductor is halved , how does current through it change ?
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Answers
Answered by
31
Hey there!
(a) New fuse wire should be of larger radius than the earlier one. We know, Resistivity of a material is directly proportional to the square of raduis of the wire. So, larger area is needed to sustain the current of 10A which is more than the earlier one (5A)
(b) Resistance of the conductor
= Resistivity/ Area of cross section
So, when raduis is halved, Area became 1/4th. Then, the resistance will increase 4 times.
Thus, the current became 1/4th if potential difference remains the same.
If the conductor have zero resistance, then the current will not change.
Hope helped.
(a) New fuse wire should be of larger radius than the earlier one. We know, Resistivity of a material is directly proportional to the square of raduis of the wire. So, larger area is needed to sustain the current of 10A which is more than the earlier one (5A)
(b) Resistance of the conductor
= Resistivity/ Area of cross section
So, when raduis is halved, Area became 1/4th. Then, the resistance will increase 4 times.
Thus, the current became 1/4th if potential difference remains the same.
If the conductor have zero resistance, then the current will not change.
Hope helped.
Magnetron:
You ignored the factor of heat capacity in your answer which has a major effect.
yea. I included about area only as per the question ^^
Heat capacity is directly proportional to radius cubed, if you think.
I was answering directly. pls forgive for those mistakes..!! :)
or if it lacks something. I apologise.. but answer is right, as per as the question. :)
Alright, never mind, I realized its a class 10 question.
yea
thanks for brainliest
Thanks for your help
wc
Answered by
14
Heya maye....
A)The new fuse wire should have large radius because current is inversely proportional to the resistance of the conductor and resistance of a conductor decreases on increasing the radius of conductor.
B)Resistance of a conductor wire
= R = Resistivity * Length/Area of cross-section
So if radius is halved, Area becomes1/4th and so resistance becomes 4 times.
So current becomes 1/4th, if the potential difference across the conductor remains same.
Hope help
@skb♥️
A)The new fuse wire should have large radius because current is inversely proportional to the resistance of the conductor and resistance of a conductor decreases on increasing the radius of conductor.
B)Resistance of a conductor wire
= R = Resistivity * Length/Area of cross-section
So if radius is halved, Area becomes1/4th and so resistance becomes 4 times.
So current becomes 1/4th, if the potential difference across the conductor remains same.
Hope help
@skb♥️
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