Question

answer. class test is s there

in 2 mins ​

Answer 1

Answer:

$\huge\bold{\underline{\underline{{Answer:-}}}}$

$\sqrt[3]{512 \times 343}$

$resolving \:512 \: and \: 343\: into \: prime \: factors$

$512 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2$

$343 = 7 \times 7 \times 7$

$\sqrt[3]{512} = 2 \times 2 \times 2 = 8$

$\sqrt[3]{343} = 7$

$hence \: \: \: \: \: \sqrt[3]{512 \times 343}$

$\sqrt[3]{8 \times 7}$

$\sqrt[3]{56}$

= 56

Answer 2

Answer:

Answer:

\huge\bold{\underline{\underline{{Answer:-}}}}Answer:−

\sqrt[3]{512 \times 343}3512×343

resolving \:512 \: and \: 343\: into \: prime \: factorsresolving512and343intoprimefactors

512 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2512=2×2×2×2×2×2×2×2×2

343 = 7 \times 7 \times 7343=7×7×7

\sqrt[3]{512} = 2 \times 2 \times 2 = 83512=2×2×2=8

\sqrt[3]{343} = 73343=7

hence \: \: \: \: \: \sqrt[3]{512 \times 343}hence3512×343

\sqrt[3]{8 \times 7}38×7

\sqrt[3]{56}356

= 56