Question

" ANSWER CORRECTLY "

Answer 1

From the given figure, we know that ∆AQD is a right angled triangle where Q is the right angle.

So , by pythagoras theorem , we can find side AD .

Hypo² = base² + height²

AD² = QD² + QA²

AD² = 4² + 3²

AD = √16 + 9

AD = √25

AD = 5 cm

.

.

Side of the square = AD = 5cm

hence , area of square = side²

= 25 cm²

answer : 25cm²

Answer 2

Answer:

triangle AQD is a right angled triangle

by pythagores theorm,

(AD)²=( AQ)²+(QD)²

= (3)²+(4)²

=9+16

=25

therefore AD=√25=5cm

side of a square now as AD is side of square also which is the hypotenous of triangle so

area of Square=side×side

=5×5

=25cm²