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Hey there,
If the perimeter of square=40 cm
One side=40/4 cm=10 cm
So the area=10cm*10cm=100cm²
Since their is difference of 9cm² between square and rectangle so the area of rectangle is either 100+9=109cm² or 100-9=91cm²
Since 13cm*7cm=91 cm²
and perimeter if sides are 7cm and 13 cm=40cm so it satisfy both conditions.
Hence required sides are 7cm and 13 cm.
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
If the perimeter of square=40 cm
One side=40/4 cm=10 cm
So the area=10cm*10cm=100cm²
Since their is difference of 9cm² between square and rectangle so the area of rectangle is either 100+9=109cm² or 100-9=91cm²
Since 13cm*7cm=91 cm²
and perimeter if sides are 7cm and 13 cm=40cm so it satisfy both conditions.
Hence required sides are 7cm and 13 cm.
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Answered by
0
perimeter of square = 4×side
40=4×side
side=10
perimeter of rectangle=2(sum of sides)
40=2(sum of sides)
sum of sides=20
area of square=100
area of rectangle=product of sides
100-product of sides=9
product of sides=91
so the possible dimensions of rectangle are13&7
40=4×side
side=10
perimeter of rectangle=2(sum of sides)
40=2(sum of sides)
sum of sides=20
area of square=100
area of rectangle=product of sides
100-product of sides=9
product of sides=91
so the possible dimensions of rectangle are13&7
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