Question

answer fast!!!!!!!!!!!!!!!!

Answer 1

$Given : \frac{7 + \sqrt{5} }{7 - \sqrt{5} } - \frac{7 - \sqrt{5} }{7 + \sqrt{5} }$

$\frac{(7 + \sqrt{5})^2 - (7 - \sqrt{5} )^2 }{(7 - \sqrt{5})(7 + \sqrt{5}) }$

$\frac{(49 + 5 + 14 \sqrt{5} ) - (49 + 5 - 14 \sqrt{5}) }{(7)^2 - ( \sqrt{5} )^2}$

$\frac{49 + 5 + 14 \sqrt{5} - 49 - 5 + 14 \sqrt{5} }{49 - 5}$

$\frac{28 \sqrt{5} }{44}$

$\frac{7 \sqrt{5} }{11}$

$0 + \frac{7 \sqrt{5} }{11}$

$0 + 1 * \frac{7 \sqrt{5} }{11}$



Therefore a = 0, b = 1.


Hope this helps!

Answer 2

Hi there !!
a = 0
b = 1

Method is in the attachment :D