Question

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A 13 metre long ladder when set against the wall of a house reaches a height of 12 m how far is the foot of the ladder from the wall ?​

Answer 1

Answer:

5m

Given,

Ladder height = 13 m, Wall height = 12 m.

To Find,

Foot of the ladder = ?

Solution,

Let the ladder height (13m) = AB

Let the vertical height (12m) it reached = AC.

Let the distance = BC = x meters.

By Pythagoras theorem,

AB^2 = AC^2 + BC^2

=> 13^2 = 12^2 + x2

=> 169 - 144 = x^2

=> x = 5 m

Result,

Foot of the ladder from the wall is 5m from the wall.

#Hope my answer helped you.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{ BC=5m}}}$

$\pink{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \text{Given : }} \\ \implies \text{ Length \: of \: ladder = 13 m} \\ \\ \implies \text{Height \: of \: wall = 12 m} \\ \\ \red{ \underline \text{To \: Find : }} \\ \implies \text{Distance \: between \: foot \: of \: wall \: and \: ladder = ?}$

• According to given question :

$\bold{Phythagoras \: theoram : } \\ \circ \: \text{According \: to \: phythagoras \: theoram : } \\ \circ \text{\:Square \: of \: longest \: side \: is \: equal} \\ \: \: \text{ to \: the \: sum \: of \: square \: of} \\ \: \: \: \text{other \: two \: sides : } \\ \\ \circ \: \bold{In \: Right \: triangle \: ABC} \\ \implies {h}^{2} = {p}^{2} + {b}^{2} \\ \\ \implies {AC}^{2} = {AB}^{2} + {BC}^{2} \\ \\ \implies {13}^{2} = {12}^{2} + {BC}^{2} \\ \\ \implies 169 - 144 = {BC}^{2} \\ \\ \implies {BC}^{2} = 25 \\ \\ \implies BC = \sqrt{25} \\ \\ \green{\implies \text{BC = 5 m}}$