answer fast guys....
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Here I am writing theta as A. Because it is difficult for me to write theta always.
Given sinA + cosA = root 2.
On Squaring both sides, we get
(Sin A + cos A)^2 = (root 2)^2
sin^2A + cos^2A + 2sinAcosA = 2
Note: We know that sin 2A = 2sinAcosA
1 + sin2A = 2
sin2A = 1
sin2A = sin90
2A = 90
A = 45.
Hope this helps!
Given sinA + cosA = root 2.
On Squaring both sides, we get
(Sin A + cos A)^2 = (root 2)^2
sin^2A + cos^2A + 2sinAcosA = 2
Note: We know that sin 2A = 2sinAcosA
1 + sin2A = 2
sin2A = 1
sin2A = sin90
2A = 90
A = 45.
Hope this helps!
siddhartharao77:
No problem
Answered by
0
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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