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Given,
AB || CF
angle BCA = 65°
angle ABC = 40°
•°• angle BCF = 40°
•°• angle BCA + angle BCF + angle FCD = 180°
=> 65° + 40° + angle FCD = 180°
=> 105° + angle FCD = 180°
=> angle FCD = 180°-105°
=> angle FCD = 75°
Now,
CD || EF
•°• angle x = angle FCD
=> angle x = 75°
AB || CF
angle BCA = 65°
angle ABC = 40°
•°• angle BCF = 40°
•°• angle BCA + angle BCF + angle FCD = 180°
=> 65° + 40° + angle FCD = 180°
=> 105° + angle FCD = 180°
=> angle FCD = 180°-105°
=> angle FCD = 75°
Now,
CD || EF
•°• angle x = angle FCD
=> angle x = 75°
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