Question

answer fast no useless answer

Answer 1

GIVEN: Angle A = 130°

TO FIND : Angle DPE = Angle CPB =?

Let angle B be 2x

So, angle C = 180 - (130 +2x) = 50–2x

So angle DCB =(50–2X)/2

Now, angle CDA = 2x + (50–2x)/2 ( as exterior angle = the sum of 2 opposite interior angles)

=> angle CDA = (2x +50)/2 = x+ 25 ……..(1)

Now,in triangle AEB, angle AEB =180 - (130+x) = 50 -x ………….(2)

So, in quadrilateral ADPE,

angle DPE = 360 -(130 + x+25 + 50-x)

=> angle DPE = 360- 205

=> angle DPE = 155°