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abc= 1
1/(1+ b+ c^-1) = c/( c+ bc + 1)
bc = 1/a
c/( c + 1/a +1)
ca/( ca + a + 1)
1/( 1+ a+ b^-1) = b/( b + ab +1)
ab = 1/c
= b/( 1/ca. + 1/c + 1)
= bca /( 1+ a + ca)
= 1/( 1+ a+ ca)
1/( 1+ c+ a^-1) = a/( a+ ca +1)
So
ca/( ca+ a+ 1) + 1/( 1+ a+ ca) + a/(a+ ca+ 1)
ca+ 1+ a)/( ca+ a+ 1)
1
(2) 1 is correct✌✌✌
Anonymous:
hi
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