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12.) 2) x=50°
13.) 4) 119° , 119°
Step-by-step explanation:
✧ Given:-
(i) The angles on the line are (x+20)° , (x+3)° and (x+7)°.
(ii) ∠1=∠2 and ∴ ∠3=∠4 and an unequal angle in the triangle is 58°.
✧ To Find:-
(i) The Value of x.
(ii) Measure of ∠3 and ∠4.
✧ We Know That:-
- Sum of all the angles on a line is 180°.
- Sum of all angles of a triangle is 180°.
✧ Solution:-
(i) According to the Question:-
⇒ (x+20)+(x+3)+(x+7)=180
⇒ 3x+30=180
⇒ 3(x+10)=180
⇒ x+10=60
⇒ x=60-10
→ x=50°
(ii) In Δ,
58+∠1+∠2=180
⇒ 50+∠2+∠2=180
⇒ 2∠2=180-58
⇒ ∠2=
⇒ ∠2=61°
∴ ∠1=∠2=61°
Now,
∠3+∠1=180°
⇒ ∠3+61°=180°
⇒ ∠3=180°-61°
⇒ ∠3=119°
→ ∠3=∠4=119°
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