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Explanation:
The mass of 22.4l of CO2 at STP = 44g
The mass of 1120l CO2 liberated = (1120 * 44)/ 22.4 = 2200 grams =500 moles
Mass of CaCO3 required to liberate 2200 grams of CO2
CaCO3 -----> CO2 +CaO
1 -----> 1 :: 1
? -------->500 moles
500 moles of CaCO3 are required = 50000 grams of CaCO3
60/100 of 50000 = 30000 grams of CaCO3
so I guess
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