Chemistry, asked by daredevilsurya84, 27 days ago

Answer fast plz !!! It would help me

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Answered by Rajkd180203
0

Answer:

Explanation:

The mass of 22.4l of CO2 at STP = 44g

The mass of 1120l CO2 liberated = (1120  * 44)/ 22.4 =  2200 grams =500 moles

Mass of CaCO3 required to liberate 2200 grams of CO2

CaCO3 -----> CO2 +CaO

    1        ----->  1 ::  1

 ?        -------->500 moles

500 moles of CaCO3 are required = 50000 grams of CaCO3

60/100 of 50000 = 30000 grams of CaCO3

so I guess

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