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Answer 1

Answer:

Explanation:

According to reaction

1 mol of CaCO3 ------------------>release 1 mol of CO2

GMM of CaCO3 ------------------> GMM of CO2

100g of CaCO3---------------------> 44 g of CO2

Therefore, release of 44g CO2 or 1 mole of CO2 or 22.4lt of CO2 is released.

            1 mol of CaCO3 ------------------> 2 mol of HCl

            100g of CaCO3-------------------> 73g of HCl

            10g of CaCO3-----------------------> 7.3g of HCl

therefore 10g of CaCO3 will yield 7.3g of HCl