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Answered by
27
Given :-
- Initial Velocity = 0m/s.
- Final Velocity = 40km/h = 11.11m/s.
- Time = 10 min = 600 seconds.
To Find :-
- Acceleration Of Train.
Solution :-
Use First Equation Of Kinematics.
v = u + at.
Here,
v = Final Velocity,
u = Initial Velocity,
a = Acceleration,
t = Time.
Put the values.
➨ 11.11 = 0 + 600a.
➨ 600a = 11.11
➨ a = 11.11/600
➨ a = 0.0185m/s²
Hence, Acceleration = 0.0185 m/s²
Answered by
19
Answer:
acceleration = 0.0185 m/s^2
Explanation:
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