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The domain of the of the function f given by f(x) = sqrt(a - x) + 1/(sqrt(x ^ 2 - a ^ 2)) * i * s​

Answers

Answered by khyatiRamteke
1

Answer:

f(x)=

x−5

For f(x) to be defined, the term under the Square-root should be greater than or equal to zero.

x−5≥0

x≥5

So, the domain is [5,∞)

Now, for x−5≥0

x−5

≥0

y≥0

So, the range is [0,∞)

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