Math, asked by Aksha02, 1 year ago

answer for 1st question pls asap

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Aksha02: pls fast

Neha1254: Ar(abc)/ar( qrp)=bc

Neha1254: Bc^2/pr^2

Neha1254: Let theta A

Neha1254: 6CotA+2CosecA=cotA+5cosecA. 6CotA -cotA=5CosecA -2cosec. 5CotA=3Cosec. 5CosA/SinA= 3(1/sinA). cosA/sinA*sinA/1= 3/5. from sinA sinA will cancel and value of cos=3/5

Neha1254: Here your steps for ques.4

Answers

Answered by Neha1254

Ans of que. 1
The remainder is 3

Aksha02: but i need the steps

Aksha02: can u pls do tje the 6 th too?

Neha1254: Its ans is 10 que 6

Neha1254: Can u tell me 4 question

Neha1254: Ques no 4 ans is 3/5

Aksha02: yes crct for ans 4

Aksha02: can u pls do with steps n post

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