Question

Answer for 7and8...........

Answer 1

Q7 find the lcm of 35,56,91
and then add the lcm by 7

Answer 2

1) The smallest number which when divided by 35, 56 and 91 = LCM of 35, 56 and 91

35 = 5 x 7
56 = 2 x 2 x 2 x 7
91 = 7 x 13

LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.

2)lets say the 4 numbers are: a-3d, a-d, a+d, a+3d

where sum of 4 terms = 32,

hence 4a = 32, implies a = 8;

according to question:

(8-3d)(8+3d)/(8-d)(8+d) = 7/15

solving we get answer: 2,6,10,14