Answer for (A-B)U(B-A) in sets
Answers
A-B=A
B-A=B
(A-B) U (B-A)=AUB
Hope it helps you
Please mark as brainlist
Answer:
(A-B) ∪ (B-A) = (A ∪ B) - (A ∩ B)
Step-by-step explanation:
Let U be the universal set.
Step 1:
We know that the difference between two sets is equal to the intersection of the first set with the complement of the second set.
(A-B) ∪ (B-A)
⇒ (A ∩ B') ∪ (B ∩ A')
Step 2:
Using the distributive property of ∪ over ∩.
⇒ { (A ∩ B') ∪ B } ∩ { (A ∩ B') ∪ A'}
⇒ { (A ∪ B) ∩ (B' ∪ B) } ∩ { (A ∪ A') ∩ (B' ∪ A') }
The union of a set with it complement set gives back the universal set U.
⇒ { (A ∪ B) ∩ U } ∩ { U ∩ (B' ∪ A') }
Step 3:
The intersection of any set with the universal set is the set itself.
⇒ (A ∪ B) ∩ (A ∩ B)'
The difference between two sets is equal to the intersection of the first set with the complement of the second set.
⇒ (A ∪ B) - (A ∩ B)
Therefore, the answer for (A-B) ∪ (B-A) in sets is (A ∪ B) - (A ∩ B).
#SPJ2