Answer for both 4 questions.
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Answer:
=> 17 ) Since the process is adiabatic, there is no exchange of heat in the process, Let, pressure is increased by AP and volume is increased by AV at each stroke.
For just before and after an stroke, we can write.
Next copy in the pic .....
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=> 18)This system of two parallel springs is equivalent to a single Hookean spring, of spring constant
k
. The value of
k
can be found from the formula that applies to capacitors connected in parallel in an electrical circuit.
k=k1+k2
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=> 19 )It works on Bernoulli's principle. When high speed horizontal air passes over a vertical tube, it creates a low pressure and draws the air and liquid inside the vertical tube upward. Atomizer has a nozzle at the end of the horizontal tube which causes the liquid to break up into small drops and mixes it with the air
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=> 20)
(a) No
K.E. is not conserved during the given elastic collision, K.E. before and after collision is the same. Infact, during collision, K.E. of the balls gets converted into potential energy.
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(b) Yes
In an elastic collision, the total linear momentum of the system
always remains conserved
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