Question

answer for Brainliest
​

Answer 1

6.

Produce DC to F and let it intersect AE at G,

Therefore AB is parallel to DF

Now,

∠BAG = ∠CGE (Corresponding angles are equal)

= 105

In triangle CGE

∠CGE + ∠GEC = ∠ECD (exterior angle property)

105+25 = x

130 = x

7.

∠AOD = ∠COB (Vertically opposite angles are equal)

∠AOD = 5y

Now

∠POA+∠AOD+∠DOQ= 180 (Since its a straight line)

5y+5y+2y=180

12y=180

y=180/12

=15

HOPE THIS HELPS ^_^