Question

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Baichung's father is 26 years younger than Baichung's grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them? (ex 2.2 ncert maths)

Answer 1

let baichung's present age be x years.
given baichung's father is 29 yrs oldes than him.

baichung's father's present age is (x+29)yrs.

baichung's grandfather's present age is (x+29+26)yrs

given sum of all ages is 135 yrs.

x+(x+29)+(x+29+26)=135
3x+29+26+29=135
3x+84=135
3x=135-84=51
x=51/3=17

baichung's present age is 17yrs
his father's present age is 46yrs
his grandfather's present age is 72yrs.....HOPE THIS HELPS......REGARDS