Question

Answer for the brainliest

Answer 1

1
$1 ^{3} + 2 ^{3} + 3 ^{3} + ... + n ^{3} = \: \: (n (n + 1) \div 2) {}^{2} \\ \\ therefore \: \: \sqrt{1 {}^{3} + 2 {}^{3} + 3 {}^{3} + ...10 {}^{3} } = \sqrt{} ( 10 (1 0 + 1) \div 2) {}^{2} \\ \\ =( 10 \times 11) \div 2 \\ = 110 \div 2 \\ = 55$

Answer 2

1³=1
2³=8
3³=27
4³=64
5³=125
6³=216
7³=343
8³=512
9³=729
10³=1000.

so,
√1+8+27+64+125+216+343+512+729+1000=√3025

=55.
Tq