Question

answer for this ??????????​

Answer 1

use co-ordinate formula

Answer 2

     

See the attachment. It's a weird triangle!!!

Quadrilaterals AFDE, BDEF and CDFE are parallelograms, as they're formed by joining the midpoints of sides of the triangle ABC.

Consider AFDE.

Difference of x coordinate of D from F = 4 - 3 = 1

∴ x coordinate of A = x coordinate of E + 1 = - 3 + 1 = - 2.

Difference of y coordinate of D from F = -3 - (-2) = - 1

∴ y coordinate of A = y coordinate of E - 1 = 1 - 1 = 0.

∴ A = (-2, 0)

Consider BDEF.

Difference of x coordinate of E from D = 3 -  (- 3) = 3 + 3 = 6

∴ x coordinate of B = x coordinate of F + 6 = 4 + 6 = 10.

Difference of y coordinate of E from D = - 2 - 1 = - 3

∴ y coordinate of B = x coordinate of F - 3 = - 3 - 3 = - 6.

∴ B = (10, -6)

Consider CDFE.

Difference of x coordinate of F from D = 3 - 4 = - 1

∴ x coordinate of C = x coordinate of E - 1 = - 3 - 1 = - 4.

Difference of y coordinate of F from D = - 2 - (- 3) = 1

∴ x coordinate of C = x coordinate of E + 1 = 1 + 1 = 2.

∴ C = (-4 ,2)

Hope this helps.

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