prove √3 + √2 an irrational number
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Let √2 + √3 = (a/b) is a rational number.
On squaring both sides , we get
2 + 3 + 2√6 = (a²/b²)
So,5 + 2√6 = (a²/b²) a rational number
So, 2√6 = (a²/b²) – 5
Since, 2√6 is an irrational number and (a²/b²) – 5 is a rational number
Hence, my contradiction is wrong.
There fore, (√2 + √3) is an irrational number.
I Hope It Will Help!
^_^
Let √2 + √3 = (a/b) is a rational number.
On squaring both sides , we get
2 + 3 + 2√6 = (a²/b²)
So,5 + 2√6 = (a²/b²) a rational number
So, 2√6 = (a²/b²) – 5
Since, 2√6 is an irrational number and (a²/b²) – 5 is a rational number
Hence, my contradiction is wrong.
There fore, (√2 + √3) is an irrational number.
I Hope It Will Help!
^_^
supergiggles53:
tysm it really worked
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