Question

answer for this plz​

Answer 1

The image is 1.15 m at the back of the mirror.

Magnification, m=h'/h=-v/u=-1.15m/(-5.00m)=+0.23

The image is virtual, erect and smaller in size by a factor of 0.23.

Answer 2

f=radius/2= 1.5m

location of bus from mirror=object distance(u)=5m

using relation: 1/v+1/u=1/f

1/1.5=1/5+1/v

1/1.5-1/5=1/v

(1+0.3)/1.5=1/v

v=1.5/1.4m

since object is beyond focus the image is formed on the same side of the lens...

Nature: real and inverted