Question

answer frndz fast plz​

Answer 1

Answer:

The number that must be subtracted is

$\frac{23}{9}$

Step-by-step explanation:

Let the number that must be subtracted be x.

A/q

$5 \times \frac{1}{6} - x = 2 \times \frac{11}{18}$

$\frac{31}{6} - x = \frac{47}{18}$

$\frac{31}{6} - \frac{47}{18} = x$

LCM of 6 and 18 is 18.

$\frac{31 \times 3}{6 \times 3} - \frac{47 \times 1}{18 \times 1} = x$

$\frac{93}{18} - \frac{47}{18} = x$

$\frac{93 - 47}{18} = x$

$\frac{46}{18} = x$

$x = \frac{23}{9}$

Verification

$5 \times \frac{1}{6} - x = 2 \times \frac{11}{18}$

Let's put the value of x

$\frac{31}{6} - \frac{23}{9} = \frac{47}{18}$

LCM of 6 and 9 is 18.

$\frac{31 \times 3}{6 \times 3} - \frac{23 \times 2}{9 \times 2} = \frac{47}{18}$

$\frac{93 - 46}{18} = \frac{47}{18}$

$\frac{47}{18} = \frac{47}{18}$

Therefore the required number that must be subtracted from

$5 \times \frac{1}{6} \: is \: \frac{23}{9}$

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Answer 2

Answer:

$2 \frac{5}{9}$

Step-by-step explanation:

$5 \frac{1}{6} - x = 2 \frac{11}{18}$

$- x = 2 \frac{11}{18} - 5 \frac{1}{6}$

$- x = \frac{47}{18} - \frac{31}{6}$

$- x = \frac{47 - 93}{18}$

$- x = \frac{ - 46}{18}$

$- x = \frac{ - 23}{9}$

$x = \frac{23}{9} = 2 \frac{5}{9}$