Question

Answer:
If (x - 1)2 + (y - 3)2 + (z-5)2+(t-7)2 =0, then xyzt +16 is equal to
o 52
0 92
o 112
o 122​

Answer 1

Answer:

xyzt + 16 = 121

Step-by-step explanation:

Solution below:

(x-1) ^2 + (y-3) ^2 + (z-5) ^2 + (t-7) ^2 = 0

assuming:

x, y, z, t ∈ R

this can be re-written in the form:

a^2 + b^2 + c^2 + d^2 = 0

where,

a = (x-1)

b = (y-3)

c = (z-5)

d = (t-7)

for real numbers,

a^2 >= 0

b^2 >= 0

Answer 2

Answer:

121

Step-by-step explanation:

1. x=1,y=3,z=5,t=7
2. atp, xyzt+16
3. 1×3×5×7+16
4. 105+16
5. 121