Question

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ᴀ ʀᴇᴄᴛᴀɴɢᴜʟᴀʀ ᴠᴇssᴇʟ ᴏғ ᴅɪᴍᴇɴsɪᴏɴs 30 ᴄᴍ x 22 ᴄᴍ x 10 ᴄᴍ ɪs ᴄᴏᴍᴘʟᴇᴛʟʏ ғɪʟʟᴇᴅ ᴡɪᴛʜ ᴡᴀᴛᴇʀ. ᴛʜɪs
ᴡᴀᴛᴇʀ ɪs ᴘᴏᴜʀᴇᴅ ᴄᴏᴍᴘʟᴇᴛᴇʟʏ ɪɴᴛᴏ ᴀ ᴄᴏɴɪᴄᴀʟ ᴠᴇssᴇʟ ᴏғ ʙᴀsᴇ ᴅɪᴀᴍᴇᴛᴇʀ 30 CM ғɪɴᴅ ᴛʜᴇ ʜᴇɪɢʜᴛ ᴏғ ᴡᴀᴛᴇʀ ɪɴ ᴄᴏɴɪᴄᴀʟ ᴠᴇssᴇʟ??​

Answer 1

Answer:

$\huge{\underline{\overline{\color{darkblue}{\bf{\mid{♡AngelicDoll♡}\mid}}}}}$

$\huge\bold\green{Given :-}$

Diameter = 30 cm

Dimensions of rectangle = 30 × 22 × 10

Length = 30 cm

Breadth = 22 cm

Height = 10 cm

Volume of cuboid = $L\times{B}\times{H}$

Volume of cuboid = ${30}\times{22}\times{10}$

Volume of cuboid = $\bf\orange{6600}{cm³}$

Conical vessel diameter = 30 cm

→ Radius = $\frac{Diameter}{2}$

→ Radius = $\frac{30}{2}$

→ Radius = $\bf\orange{15}{cm}$

Volume of cone = $\frac{1}{3}$ πr²h

$\bold\frac{1}{3}\times\frac{22}{7}\times{15}\times{15}\times{h}{=}{6600}$

$\bold\frac{22}{7}\times{5}\times{15}\times{h}{=}{6600}$

$\bold{22}\times{75}\times{h}{=}{6600}\times{7}$

h = $\bold\frac{6600\times7}{22\times75}$

h = $\bold\frac{300\times7}{75}$

h = $\bold{(4\times7)cm}$

h = $\bf\orange{28~cm}$

The height of the water in the conical vessel is $\bf\blue{28}{cm}$

$<marquee>$

$\huge\red{AngelicDoll..!!!}$