Answer in detail
If possible in a picture
Question 6
Attachments:
Answers
Answered by
2
Given:
h = 7 cm
TSA = 2πr(r+h) = 4620 cm²
Area of the ring at the bottom = 115.5 cm²
Curved surface area(CSA) = TSA - Base
and Top Areas
= 4620 - 2(115.5) = 4620 - 231 = 4389 cm²
CSA = 2πrh = 438.9
2 × 3.14 × r × 7 = 438.9
r= 4389/43.96 = 9.98 cm
Base area of the cylinder = πr²
= 3.14 × 9.98 × 9.98
= 312.99 cm²
Area of base of the hollow cylinder space = 312.99 - 115.5 = 197.4 cm²
To find radius of base of the hollow cylinder,
Area = π R²
197.4 = 3.14 R²
R² = 62.86
R = 7.92 cm
Therefore,
Thickness = Radius of cylinder - Radius of hollow cylinder
= 9.98 - 7.92
Thickness of the ring = 2.06 cm.
- WonderGirl
h = 7 cm
TSA = 2πr(r+h) = 4620 cm²
Area of the ring at the bottom = 115.5 cm²
Curved surface area(CSA) = TSA - Base
and Top Areas
= 4620 - 2(115.5) = 4620 - 231 = 4389 cm²
CSA = 2πrh = 438.9
2 × 3.14 × r × 7 = 438.9
r= 4389/43.96 = 9.98 cm
Base area of the cylinder = πr²
= 3.14 × 9.98 × 9.98
= 312.99 cm²
Area of base of the hollow cylinder space = 312.99 - 115.5 = 197.4 cm²
To find radius of base of the hollow cylinder,
Area = π R²
197.4 = 3.14 R²
R² = 62.86
R = 7.92 cm
Therefore,
Thickness = Radius of cylinder - Radius of hollow cylinder
= 9.98 - 7.92
Thickness of the ring = 2.06 cm.
- WonderGirl
Anonymous:
it is better to solve surface areas and volumes on your own without any help
otherwise in exam you may not get the correct technique how to solve or the exact answer even if all your steps are right.
Yeah. You're right! But it's better to say him/her privately than saying here as it may disturb people.
Sorry...
Similar questions