find the sum of first 10 even numbers
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a=2
d=2
therefore,
S10= n/2[2a+(n-1)d]
= 10/2[4+9×2]
=5×22=110
✌️
d=2
therefore,
S10= n/2[2a+(n-1)d]
= 10/2[4+9×2]
=5×22=110
✌️
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