Question

Answer is 110 degreee and you have to show process. Pq is parallel to st . ab is a straight line find angle bst​

Answer 1

$Since, PQ∥ST</p><p>∴∠PQS=∠QST (Alternate angles)</p><p>⇒∠QST=98∘</p><p>⇒∠QSA+∠AST=98∘</p><p>⇒∠AST=98∘−28∘=70∘</p><p>Now, AB is a straight line.</p><p>∴∠AST+∠TSB=180∘ (linear pair)</p><p>⇒∠TSB=180∘−70∘=110∘.</p><p></p><p>$