Question

answer is 16
tell how

Answer 1

Heya !!!

Take one pair of shoes as 'x'
man as 'y'
and vessel as 'z'


Now at 1st line
$x + x + x = 30 \\ \\ 3x = 30 \\ \\ x = \frac{30}{3} \\ \\ x = 10$
so (one pair of shoes) = x = 10


Now in 2nd line
man is having vessel (hanged on his neck)
so, man is 'y'and vessel = 'z'
so man with vessel = (y+z)
$x + (y + z) + (y + z) = 20 \\ put \: \: value \: \: of \: x \: = 10 \\ \\ 10 + 2(y + z) = 20 \\ \\ 2(y + z) = 20 - 10 \\ \\ 2(y + z) = 10 \\ \\ (y + z) = \frac{10}{2} \\ \\( y + z) = 5$

so man with vessel =(y+z) = 5


Now in 3rd line
(man with vessel) + (2 vessels )+(2vessels) = 13

man = y and vessel = z

man with vessel = (y+z)
$so \\ ( y+z ) + 2z + 2z = 13 \\ \\ put \: \: value \: \: of \: (y + z) = 5 \\ \\ 5 + 2(2z) = 13 \\ \\ 5 + 4z = 13 \\ \\ 4z = 13 - 5 \\ \\ 4z = 8 \\ \\ z = \frac{8}{4} \\ \\ z = 2$

so z = 2
as (y+z) = 5 ,and z = 2
so,
y+2 = 5
y = 5 - 2
y = 3

so man without vessel = 3

so,
(one pair of shoes) = x = 10
(man without vessel) = y = 3
(vessel) = z = 2


Now in 4th line
the man is having no vessel

one pair of shoes = x = 10
man = y = 3
vessel = z = 2

so,
$x + y \times z \\ \\ 10 + 3 \times 2 \\ using \: \: bodmas \: \: rule \\ (3 \times 2 = 6) \\ \\ \\ 10 + 6 = 16$

So 16 is the final answer


Hope it helps

Answer 2

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2 shoes =10

1shoe=5

1man=3

2whistle=4

1whistle=2

10+10+10=30

10+3+2+3+2=20

3+2+4+4=13

10+3×2=16