answer is (2)plz tell how it comes
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Given
V=5v
r1=5
r2=8
r3=12
He told in any "arrangement"
Now we have to connect the three resistors first in series then parallel then one series and two parallel then two series one parallel (by interchanging the values only for condition 3 and 4)
So case 1 All in series
R(s)=r1+r2+r3
R(s)=5+8+12=25 is eff resistance in series
so now r=5 and v=5
I=V/R =5/5=1A is the maximum flow
the same thing happens in all the cases
because we are considering only the resistance 5 not the equivalent resistance of circuits.
Hope u understood well...........
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