Question

Answer is 60 I want statement in a mixture of 60 litres the ratio of milk and water is 2:1 If the ratio of milk and water is to be 1:2 then the amount of water (in litres) to be futher added is​

Answer 1

Step-by-step explanation:

Given :-

The ratio of milk and water in a mixture of 60 litres is 2:1

To find :-

The amount of water in the mixture if the ratio of milk and water is 1:2

Solution :-

Given that

Total amount of mixture = 60 litres

The ratio of milk and water in the mixture = 2:1

Let they be 2X litres and X litres

Total mixture = 2X+X = 3X litres

Therefore, 3X = 60

=> X = 60/3

=> X = 20 litres

If X = 20 then 2X = 2(20) = 40 litres

Therefore,

Amount of Milk in the mixture

= 40 litres

Amount of Water in the mixture

= 20 litres

Let the amount of water is added to get required ratio be Y litres

New amount of water in the mixture

= (20+Y) litres

Then, The new ratio of milk and water

= 40 : (20+Y)

According to the given problem

New ratio of milk and water = 1:2

=> 40 : (20+Y) = 1:2

=> 40/(20+Y) = 1/2

On applying cross multiplication then

=> (20+Y)×1 = 40×2

=> 20+Y = 80

=> Y = 80-20

=> Y = 60 litres

Therefore,

The amount of water = 60 litres

Answer:-

The amount of water to be further added to get required ratio is 60 litres

Used formulae:-

→ a:b can be written as a/b

Answer 2

Information provided with us:

In a mixture of 60 litres the ratio of milk and water is 2:1

After adding further amount of water in milk there Ratio becomes 1:2

What we have to calculate :

The amount of water (in litres) to be futher added

Performing Calculations :

• Initial quantity of milk in 60 litres

$\rm\longmapsto \: ( 60 \times \dfrac{2}{3} \: litres)$

$\longmapsto \: \sf{40 \ \: litres}$

• Initial quantity of water in 60 litres

$\rm\longmapsto \: ( 60 \times \dfrac{1}{3} \: litres)$

$\longmapsto \: \sf{20 \ \: litres}$

$\rm \bigstar \: New \: Ratio = 60:20$

$\rm \implies1:2$

Consider :

• Let us assume that y litres of water be added to it

Then :

$\sf :\longmapsto \: { water : milk = 1 : 2 }$

$: \longmapsto \: \sf{ \dfrac{water}{milk} = \dfrac{1}{2} }$

$: \longmapsto \: \sf{ \dfrac{40}{20 + y} = \dfrac{1}{2} }$

• By cross multiplication ❌

$: \longmapsto \: \sf{ 80 = 20 + y }$

$: \longmapsto \: \sf{ 20 + y = 8 0}$

$: \longmapsto \: \sf{ y = 8 0 - 20}$

$\red{\boxed{\bf:\longmapsto \: {y\: = \: 60 \: litres}}}$

Therefore :

$\underline{\bf{Henceforth, \: quantity \: of \: water \: to\: be \:further\:added \: is}}$

$\pink{\boxed{\bf:\longmapsto \: {quantity= \: 60 \: litres}}}$