Physics, asked by Anonymous, 4 months ago

Answer it.....

dy=e^-t/3 dt y=?

Answers

Answered by Anonymous
2

\huge\tt\red{Answer}

f \: dy \:  =  \:  {e}^{ \frac{ - t}{3} }  \: dt  \\  \\ y \:  =  \:  \frac{ {e}^{  \frac{ - t}{3} } }{ \frac{ - 1}{3} }  \:  +  \: c \\  \\ y \:  =  \:  - 3 {e}^{  \frac{ - 1}{3} }  \:  +  \: c

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