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Answered by Z69
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1.1 f(1)=3 and f(a+h)=a2+2ah+h2−3a−3h+5

1.2 Domain = {x|x≤2}, range = {y|y≥5}

1.3 x=0,2,3

1.4 (fg)(x)=x2+32x−5. The domain is {x|x≠52}.

1.5 (f∘g)(x)=2−5x−−√.

1.6 (g∘f)(x)=0.63x

1.7 f(x) is odd.

1.8 Domain = (−∞,∞), range = {y|y≥−4}.

1.9 m=1/2. The point-slope form is y−4=12(x−1). The slope-intercept form is y=12x+72.

1.10 The zeros are x=1±3–√/3. The parabola opens upward.

1.11 The domain is the set of real numbers x such that x≠1/2. The range is the set {y|y≠5/2}.

1.12 The domain of f is (−∞, ∞). The domain of g is {x|x≥1/5}.

1.13 Algebraic

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