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Answer 1

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$let \: z \: = \frac{4 { }^{5 } \times a { {}^{8}b {}^{3} } }{4 {}^{5} \times a {}^{5} b {}^{2} } \\ using \: lay \: of \: exponents \\ z = 4 {}^{5 {} - {5} } \times a {}^{8 - 5} .b {}^{3 - 2 } \\ z = 1 \times a {}^{3} .b = a {}^{3} b \\ hence \: \frac{4 {}^{5} \times a {}^{8} b {}^{3} }{4 {}^{5} \times a {}^{5} b {}^{2} } = a {}^{3} b.$

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